Question

Anybody know this answer?​

Answer 1

y = x + 5

Explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

Calculate m using the slope formula

m =
`(y_(2)-y_(1) )/(x_(2)-x_(1) )`

with (x₁, y₁ ) = (- 5, 0) and (x₂, y₂ ) = (0, 5) ← 2 points on the line

m =
`(5-0)/(0+5)` =
`(5)/(5)` = 1

The line crosses the y- axis at (0, 5 ) ⇒ c = 5

y = x + 5 ← equation of line

Answer 2

y = x + 5

Explanation:

Find any two points:

(1, 6)

(2, 7)

Slope = (y2 - y1) / (x2 - x1)

S0:

7 - 6 / 2 - 1

1 / 1

So slope = 1

Equation:

y = mx + b

Plug in the numbers using the x and y of any points:

7 = m * 2 + b

Add m (which is the slope):

7 = 1 * 2 + b

7 = 2 + b

Subtract two from both sides:

5 = b

So our equation is:

y = x + 5

Please let me know if I've done anything wrong!