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Two friends are each driving a car down Highway 101. During a particular 10 s interval, Jodi's car moves at a constant 60 mph. During that same time interval, Julie's car transitions from a speed of 20 mph to a speed of 30 mph. Whose car has the greater acceleration?

User Susam Pal
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1 Answer

1 vote

Answer:

Julie's car.

Step-by-step explanation:

The acceleration of an object is equal to the rate of change of velocity. It can be given by :


a=(v-u)/(t)

Jodi's car moves at a constant 60 mph for 10 s.

Julie's car transitions from a speed of 20 mph to a speed of 30 mph for the same time interval i.e. 10 s.

For Jodi's car, the change in velocity is equal to 0. As a result, its acceleration is equal to 0 m/s².

For Julie's car,

Initial speed, u = 20 mph = 8.9408 m/s

Final speed, v = 30 mph = 13.4112 m/s

Acceleration,


a=(13.4112-8.9408)/(10)\\\\a=0.447\ m/s^2

It is clear that Julie's car has the greater acceleration than the Jodi's car.

User Michael Queue
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