1 Answer

Miel · Answer 1 · 2021-10-30T21:12:30+0000

Given:

Last season Steven missed 24% of the free throws in his basketball games.

Free throws in the first two games of this season = 25

His missed free throw percentage holds from last season.

To find:

The number of throws Steven miss during these two games.

Solution:

His missed free throw percentage for this season = His missed free throw percentage of last season = 24%

Free throws in the first two games of this season = 25

So, the number of throws Steven miss during these two games is

$24\%\text{ of }25=(24)/(100)* 25$

$24\%\text{ of }25=(24)/(4)$

$24\%\text{ of }25=6$

Therefore, Steven miss 6 free throws during these two games.

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