Question

suma is twice as old as her brother. in 6 years time,the sum of their ages will be 39 years.what is her age now?​

Answer 1

18

Explanation:

In 6 years, both other their ages will add up to 39. So 12 years back( 6 years for each of them), their combined age will be 27.

Now we have to find the age of Suma. We can find her brother age first.

We can use the equation 2x+x=27

In this equation, x is the age of Suma's brother. 2x + x = 3x.

3x = 27.

27 divided by 3 is 9 so Suma's brother is 9 years old. And since Suma is twice as old. Suma is 18 years old.

Answer 2

Suma is 18 years old

Explanation:

Let s = Suma's age

Let b = brother's age

Suma is twice as old as her brother:

⇒ s = 2b

In 6 years time, the sum of their ages will be 39 years:

⇒ (s + 6) + (b + 6) = 39

Substitute s = 2b into (s + 6) + (b + 6) = 39 and solve for b:

⇒ (2b + 6) + (b + 6) = 39

⇒ 3b + 12 = 39

⇒ 3b = 27

⇒ b = 9

Substitute found value of b into s = 2b and solve for s:

⇒ s = 2(9)

⇒ s = 18

Therefore, Suma is 18 years old and her brother is 9 years old.