Question

Dennis the Menace uses his slingshot to shoot a small rock at his neighbor's flowerpots. The rock travels a distance of 12.5 cm from the point at which he pulls it back to the point at which it leaves the slingshot. It leaves the slingshot at a velocity of 6.24 m/s. Find the average acceleration of the rock.

Answer 1

`a=155.750\ m/s^2`

Step-by-step explanation:

It is given that,

A small rock is shoot at Dennis' neighbor's flowerpots. The rock travels a distance of 12.5 cm from the point at which he pulls it back to the point at which it leaves the slingshot.

Final velocity of the rock, v = 6.24 m/s

The initial velocity of the rock, u = 0 (as it was at rest)

Let a is the acceleration of the rock. It can be calculated using the equation of kinematics as follows :

`v^2-u^2=2ad\\\\\text{Put u = 0 }\\\\v^2=2ad\\\\a=(v^2)/(2d)\\\\a=((6.24)^2)/(2* 12.5* 10^(-2))\\\\a=155.750\ m/s^2`

So, the average acceleration of the rock is
`155.750\ m/s^2`.