Question

As a fish jumps vertically out of the water, assume that only two significant forces act on it: an upward force F exerted by the tail fin and the downward force due to gravity. A record Chinook salmon has a length of 1.50 m and a mass of 46.0 kg. If this fish is moving upward at 3.00 m/s as its head first breaks the surface and has an upward speed of 5.80 m/s after two-thirds of its length has left the surface, assume constant acceleration and determine the following.

a. The salmon's acceleration
b. The magnitude of the force F during this interval N

Answer 1

a

`a =  12.32 \  m/s^2`

b

`F = 1017.52 \  N`

Step-by-step explanation:

From the question we are told that

The length of the Chinook salmon is
`l =  1.50 \  m`

The mass of the Chinook salmon is
`m  =  46.0 \ kg`

The upward velocity in water is
`u =  3.00 \ m/s`

The upward velocity in air is
`v =  5.80 \ m/s`

Generally from kinematic equations

`v^2  =  u^2 +  2as`

=>
`5.80^2  =  3.00^2 +  2  *  a *  [ [(2)/(3) * l ]`

=>
`5.80^2  =  3.00^2 +  2  *  a *  [ [(2)/(3) * 1.5 ]`

=>
`5.80^2  =  3.00^2 +  2  *  a *  [1 ]`

=>
`a =  12.32 \  m/s^2`

Generally magnitude of the force F during this interval in N is mathematically represented as

`F  =  m (a + g )`

=>
`F  =  46.0 (12.32 + 9.8 )`

=>
`F = 1017.52 \  N`