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As a fish jumps vertically out of the water, assume that only two significant forces act on it: an upward force F exerted by the tail fin and the downward force due to gravity. A record Chinook salmon has a length of 1.50 m and a mass of 46.0 kg. If this fish is moving upward at 3.00 m/s as its head first breaks the surface and has an upward speed of 5.80 m/s after two-thirds of its length has left the surface, assume constant acceleration and determine the following.

a. The salmon's acceleration
b. The magnitude of the force F during this interval N

1 Answer

2 votes

Answer:

a


a =  12.32 \  m/s^2

b


F = 1017.52 \  N

Step-by-step explanation:

From the question we are told that

The length of the Chinook salmon is
l =  1.50 \  m

The mass of the Chinook salmon is
m  =  46.0 \ kg

The upward velocity in water is
u =  3.00 \ m/s

The upward velocity in air is
v =  5.80 \ m/s

Generally from kinematic equations


v^2  =  u^2 +  2as

=>
5.80^2  =  3.00^2 +  2  *  a *  [ [(2)/(3) * l ]

=>
5.80^2  =  3.00^2 +  2  *  a *  [ [(2)/(3) * 1.5 ]

=>
5.80^2  =  3.00^2 +  2  *  a *  [1 ]

=>
a =  12.32 \  m/s^2

Generally magnitude of the force F during this interval in N is mathematically represented as


F  =  m (a + g )

=>
F  =  46.0 (12.32 + 9.8 )

=>
F = 1017.52 \  N

User Neal Richardson
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