Question

Normally the capital ÎGo° for a reaction would be determined at standard temperature with each reactant at a concentration of 1 M. Letâs assume that the 1 M 2-PG solution will reach the same equilibrium ratio that would be observed under standard conditions. The enzyme enolase catalyzes the conversion of 2-PG to phosphoenolpyruvate (PEP) in living systems. You find that when you add enolase to your 2-PG solution it reaches an equilibrium with 0.68M PEP and 0.32 M 2-PG. What is the capital ÎGo° for this reaction?

Use R= 1.987 cal/mol.K

a. +559 cal/mol
b. - 559 cal/mol
c. +379 cal/mol
d.-379 cal/mol

Answer 1

d.-379 cal/mol

Step-by-step explanation:

ΔG = ΔG⁰ + RT ln K

for equilibrium ΔG = 0

ΔG⁰ + RT ln K =0

ΔG⁰ = - RT ln K

PG ⇒ PEP

K = [ PEP ] / [ PG ]

= .68 / .32

= 2.125

ΔG⁰ = - 1.987 x 273 x ln 2.125

= - 409 Cal / mole

Option d is the nearest answer .