Question

What are the solutions of the quadratic equation 4x^2-8x-12=0

Answer 1

x₁ = -1, x₂ = 3

Explanation:

`4x^2-8x-12=0\\{}\qquad\qquad^(/4\qquad/4)\\x^2-2x-3=0\\\\x^2+x-3x-3=0\\\\x(x+1)-3(x+1)=0\\\\(x+1)(x-3)=0\\\\x+1=0\quad\vee\quad x-3=0\\\\x=-1\quad\vee\quad x=3`