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Plot the x intercepts,maxima and minima of y=cos(x) from 0 to 2pi

User Ritmatter
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1 Answer

3 votes

Answer:

Figure of the function is included below as attachment.

Explanation:

Let
y = \cos xAs first step we have to find x intercepts, maxima and minima from 0 to 2π, which are needed to plot given function. Cosine is a trigonometric function bounded between -1 and 1 with a periodicity of 2π.

x-Intercepts

x-intercepts are those points of the function such that
y = 0. That is:


\cos x = 0

In this case, there is a periodicity of π for
y = 0. The x-intercepts are in the following set:


S = \{\forall\,x\in\mathbb{R}|x=0.5\pi\pm\pi\cdot i,i\in\mathbb{N}_(O) \}

Maxima

Maxima are those points of the function such that
y = 1. That is:


\cos x = 1

In this case, there is a periodicity of 2π for
y = 1. Maxima are in the following set:


S = \{\forall\,x\in\mathbb{R}|x=0\pm2\pi\cdot i,i\in\mathbb{N}_(O) \}

Minima

Minima are those points of the function such that
y = -1. That is:


\cos x = -1

In this case, there is a periodicity of 2π for
y = -1. Minima are in the following set:


S = \{\forall\,x\in\mathbb{R}|x=\pi\pm2\pi\cdot i,i\in\mathbb{N}_(O) \}

Lastly, we proceed to plot the function as well as its x-intercepts, maxima and minima with the help of a plotting tool.

Plot the x intercepts,maxima and minima of y=cos(x) from 0 to 2pi-example-1
User Matthew Alpert
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5.9k points