Answer:
[1/7 x - 1/5][(1/49 x²)+(1/35 x)+(1/25)]
(0.1b - 2)[0.01b²+0.2b+4]
Explanation:
a³-b³=(a-b)(a²+ab+b²)
So
1/343 x³ - 1/125
[(1/7)x]³ - [1/5]³
[1/7 x - 1/5][(1/7 x)²+(1/7 x)(1/5)+(1/5)²]
[1/7 x - 1/5][(1/49 x²)+(1/35 x)+(1/25)]
And
0.001b3 - 8
(0.1b)³-(2)³
(0.1b - 2)[(0.1b)²+(0.1b)(2)+2²]
(0.1b - 2)[0.01b²+0.2b+4]