Question

how much time does it required for an airplane to reach its take off speed of 77 m/s if it starts from rest and its average acceleration is 8.2 m/s^2

Answer 1

t = 9.38 seconds

Step-by-step explanation:

Given that,

Initial speed of the airplane, u = 0 (at rest)

Final speed of the airplane, v = 77 m/s

Acceleration of the airplane, a = 8.2 m/s²

We need to find the time required for the airplane to accelerate. The formula of acceleration is given by :

`a=(v-u)/(t)\\\\t=(v-u)/(a)\\\\t=(77-0)/(8.2)\\\\t=9.38\ s`

So, the time taken by the airplane is 9.38 seconds.