Answer:
- Krypton.
- Silicon.
Step-by-step explanation:
Hello.
In this case, since the first element's last term in the electron configuration is 4p⁶, by looking at the fourth period, the only element having sic 4p electrons is Kr as its electron configuration is:
![Kr^(36):1s^2,2s^2,2p^6,3s^2,3p^6,4s^2,3d^1^0,4p^6](https://img.qammunity.org/2021/formulas/chemistry/college/f2r49j5zk6yu5iqe4bl7a2sg6f8bfuiz4b.png)
In the second case, the element of the third period having two 3p electrons or
the last term in its electron configuration is silicon as shown below:
![Si^(14):1s^2,2s^2,2p^6,3s^2,3p^2](https://img.qammunity.org/2021/formulas/chemistry/college/n251cg5csa2yticuy2cybhxcldc72v0j43.png)
Best regards.