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An 800 kg car exerts 4000N of applied force on a level road while

being opposed by 700 N of friction. Determine the acceleration of the car.

An 800 kg car exerts 4000N of applied force on a level road while being opposed by-example-1
User A Paracha
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1 Answer

4 votes

Answer:

a = 4.125 [m/s^2]

Step-by-step explanation:

In order to calculate the value of acceleration, we must use Newton's second law, which tells us that the sum of forces must be equal to the product of mass by acceleration.

ΣF = m*a

where:

ΣF = sum of forces [N]

m = mass [kg]

a = acceleration [m/s^2]

Performing a summation of forces on the x-axis, we have:

4000 - 700 = m*a

4000 - 700 = 800*a

a = 4.125 [m/s^2]

User Umesh Patil
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