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Factor completely P(x) = 81x^4 − 256

User Fresko
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1 Answer

3 votes

Answer:


(3x+4)(3x-4)(9x^2+16)

Explanation:

Given
p(x)=81x^4-256

Factor using difference of squares


p(x)=(9x^2-16)(9x^2+16)

Note that the factor
(9x^2-16) can still be factored using, again, difference of squares. Thus,


p(x)=(3x+4)(3x-4)(9x^2+16)

User Moad Ennagi
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