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Identify the vertex
y=x^2-2x-3

User Zrubenst
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1 Answer

3 votes

Answer:

The vertex is located at (1,-4)

Explanation:

Equation of the Quadratic Function

The vertex form of the quadratic function has the following equation:


y=a(x-h)^2+k

Where (h, k) is the vertex of the parabola that results when plotting the function, and a is a coefficient different from zero.

We have the following quadratic equation and we need to express it in vertex form. Thus, we need to complete the squares:


y=x^2-2x-3

Adding and subtracting 1:


y=x^2-2x+1-3-1

The first three terms are the square of a binomial:


y=(x-1)^2-4

Comparing to the vertex form of a quadratic equation, the vertex is at (1,-4).

The vertex is located at (1,-4)

User Vishwanath Dalvi
by
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