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16 votes
16 votes
Can you help me solve this equation? 20 POINTS

Can you help me solve this equation? 20 POINTS-example-1
User Hackernewbie
by
2.7k points

2 Answers

16 votes
16 votes

Answer:

63°

Explanation:

  • The central angle is 117°
  • The angles at the tangent are 90° each (property of tangents)

Applying the Angle Sum of Quadrilaterals,

  • 117° + 2(90°) + x° = 360°
  • 180° + x° = 243°
  • x° = 63°
User Geoff Adams
by
3.2k points
21 votes
21 votes

Answer:

x = 63

Explanation:

  • In
    \odot \:O, ML and MN are tangents from external points M at points L and N respectively. OL and ON are radii of the circle.


  • \implies ML\perp OL,\:\&\: MN \perp ON (By tangent theorem)


  • \implies m\angle MLO = m\angle MNO = 90\degree


  • m\angle LON = 117\degree (Given)

  • In quadrilateral LMNO, by interior angle sum theorem, we have:


  • m\angle LON+m\angle MOL +m\angle MON +m\angle LMN= 360\degree


  • \implies 117\degree+90\degree +90\degree +x\degree= 360\degree


  • \implies 297\degree+x\degree= 360\degree


  • \implies x\degree= 360\degree-297\degree


  • \implies x\degree= 63\degree


  • \implies\red{\boxed{\bold{ x= 63}}}
User Simon Zeinstra
by
2.6k points