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Calculate the displacement and then velocity for an object 12.77s after it is dropped.

1 Answer

5 votes

Answer:

799 m

125 m/s

Step-by-step explanation:

Take down to be positive. Given:

v₀ = 0 m/s

a = 9.8 m/s²

t = 12.77 s

Find: Δy and v

Δy = v₀ t + ½ at²

Δy = (0 m/s) (12.77 s) + ½ (9.8 m/s²) (12.77 s)²

Δy ≈ 799 m

v = at + v₀

v = (9.8 m/s²) (12.77 s) + 0 m/s

v ≈ 125 m/s

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