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1 vote
In
= 2n+2n²
find the first five terms


1 Answer

5 votes


t(n) = 2 {n}^(2) + 2n

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t(1) = 2 ({1})^(2) + 2(1)


t(1) = 2 * 1 + 2 * 1


t(1) = 2 + 2 = 4

##############################


t(2) = 2 ({2})^(2) + 2(2)


t(2) = 2 * 4 + 2 * 2


t(2) = 8 + 4 = 12

##############################


t(3) = 2 ({3})^(2) + 2(3)


t(3) = 2 * 9 + 2 * 3


t(3) = 18 + 6 = 24

##############################


t(4) = 2 ({4})^(2) + 2(4)


t(4) = 2 * 16 + 2 * 4


t(4) = 32 + 8 = 40

##############################


t(5) = 2 ({5})^(2) + 2(5)


t(5) = 2 * 25 + 2 * 5


t(5) = 50 + 10


t(5) = 60

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And we're done.

Thanks for watching buddy good luck.

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User Serp C
by
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