Answer:
![26](https://img.qammunity.org/2021/formulas/mathematics/middle-school/d3uib7ud4d90ftsqax8psjhnxa0ky7d47h.png)
Explanation:
We have:
![√(13)*√(52)](https://img.qammunity.org/2021/formulas/mathematics/high-school/t8ipjepf635egl9a6krt7tlwqyo8sgvicq.png)
Notice that 52 is the product of 13 and 4. So:
![=√(13)* √(13* 4)](https://img.qammunity.org/2021/formulas/mathematics/high-school/9n2ali5dmhbvvuirrb7jaszcolx1mb4l9w.png)
We can separate the second one:
![=√(13)*√(13)*√(4)](https://img.qammunity.org/2021/formulas/mathematics/high-school/obfz29vesqaibs2hbs2ss2n667tl3q3y72.png)
We can combine the first two:
![=√(13*13)*\sqrt4](https://img.qammunity.org/2021/formulas/mathematics/high-school/oi5y7gy1d4e724iikq2pi5kzazgple8dsj.png)
We can write
as
. So:
![=√(13^2) * \sqrt4](https://img.qammunity.org/2021/formulas/mathematics/high-school/3i92idh6kwsl8oxsygrrmerxmtgbkjhgf7.png)
The square root and the square will cancel. The square root of 4 is 2. So:
![=13*2](https://img.qammunity.org/2021/formulas/mathematics/high-school/vek9f4mw9j86a9zk1srkhwcd1w53hoklel.png)
Multiply:
![=26](https://img.qammunity.org/2021/formulas/mathematics/middle-school/7vz0vkumvaxmr0zxm2k3b5e2xnpljf8zvx.png)
Therefore:
![√(13)*√(52)=26](https://img.qammunity.org/2021/formulas/mathematics/high-school/o5imyy028n4z7k1nttoque6034y6ya9gm1.png)