Question

Solve the equation 3sin2 theta = sin e, for values of e between Oº and 360°

[A] 26.7, 153.3, 158.2, 338.2

[B] 0, 19.5, 160.5, 180.360

[C] 39.2, 140 8, 219.2 620.8

[D] 65,7 68.7; 120:1, 140.8​

Answer 1

[B] 0, 19.5, 160.5, 180, 360

Explanation:

3 sin²θ = sin θ

3 sin²θ − sin θ = 0

sin θ (3 sin θ − 1) = 0

sin θ = 0 or sin θ = ⅓

If sin θ = 0, θ = 0°, 180°, 360°.

If sin θ = ⅓, θ = 19.5°, 160.5°.