Plz help it's urgent

Question

asked Jun 15, 2021 173k views

1 Answer

Poliquin · Answer 1 · 2021-06-22T13:06:04+0000

d)

$\frac{2 {x}^(2) - xy + 2xy - {y}^(2) }{6xy - 3 {y}^(2) } = (x(2x - y) + y(2x - y))/(3y(2x - y)) = \\$

$((x + y)(2x - y))/(3x(2x - y)) = (x + y)/(3x) \\$

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e)

I think -6 should be +6

or +3x should be -3x

$\frac{ {x}^(2) + 2x + x + 2 }{ {x}^(2) + 2x + 3x + 6 } = (x(x + 2) + (x + 2))/(x(x + 2) + 3(x + 2)) = \\$

$((x + 1)(x + 2))/((x + 3)(x + 2)) = (x + 1)/(x + 3) \\$

Or

$(x(x + 2) + (x + 2))/(x(x + 2) - 3(x + 2)) = ((x + 1)(x + 2))/((x - 3)(x + 2)) = \\$

$(x + 1)/(x - 3) \\$

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f)

$\frac{ {a}^(2) - 5a - 4a + 20 }{ {a}^(2) - 5a + 2a - 10 } = (a(a - 5) - 4(a - 5))/(a(a - 5) + 2(a - 5)) = \\$

$((a - 4)(a - 5))/((a + 2)(a - 5)) = (a - 4)/(a + 2) \\$

And we're done.

Thanks for watching buddy good luck.

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