Answer:
The given linear equation are
⇒9x+3y+12=0....eq1
⇒a1 =9,b1 =3,c1 =12
⇒18x+6y+24...eq2
⇒a2 =18,b2 =6,c2 =24
⇒a1/a2 =9/18 =1/2
⇒ b1/b2= 3/6 = 1/2
⇒ c1/c2= 12/24= 1/2
comparing
⇒ a1/a2,b1/b2,c1/c2
⇒ a1/a2=b1/b2=c1/c2
Hence, the line represented by eq1 and eq2 are coincidents
Explanation: