Question

I

. During a volleyball training session, Idalie drank twice as much water as Adamaris, and Jonathan
Arank 100 mL more water than Idalie. Between them they drank 3 liters of water. How much water
did Adamaris drink?

Answer 1

Explanation:

Let's say I = amount of water Idalie drank,

A = amount of water Adamaris drank

J = amount of water Jonathan drank.

We are told Idalie drank twice as much water as Adamaris. You can write it as:

Idalie = 2 times Adamaris

I = 2A

Then we are told Jonathan drank 100ml more than Idalie. So

Jonathan = 100 + Idalie

J = 100 + I (and we know I = 2A)

J = 100 + 2A

Between them they drank 3 liters (3L = 3000ml) of water.

Idalie + Adalie + Jonathan = 3000

I + A + J = 300

So since we know I = 2A and J = 100 + 2A, we can put it into the equation above:

2A + A + 100 + 2A = 3000

Gather the like terms and you get:

5A + 100 = 3000

Subtract 100 from both sides.

5A = 3000 - 100 = 2900

To find A, divide both sides by 5

A = 2900/5 = 580

This means Adamaris drank 580ml of water