Final answer:
The momentum of a fully loaded Boeing 747 with a mass of about 4,082,331.33 kg and a cruising speed of 253 m/s is 1.03 billion kg·m/s.
Step-by-step explanation:
The momentum of an object is given by the product of its mass and velocity. Therefore, the momentum of a fully loaded Boeing 747 that has a mass of approximately 4,082,331.33 kg and is cruising at a velocity of 253 m/s can be calculated using the formula:
Momentum = Mass × Velocity
= 4,082,331.33 kg × 253 m/s
= 1,032,839,806.49 kg·m/s
The momentum of the Boeing 747 is therefore 1.03×10⁹ kg·m/s (or 1.03 billion kg·m/s), which represents the quantity of motion the airplane has while in Eastward travel.