Question

What is the density of a cube of iron that is 3 inches on each side and has a mass of 13g?

Answer 1

`\boxed {\tt 0.481481481 \ g/in^3}`

Step-by-step explanation:

Density can be found by dividing the mass by the volume.

`d=(m)/(v)`

The mass is 13 grams. Let's calculate the volume. This is a cube, so the volume formula is:

• v=s³
• The side length (s) is 3 inches
• v=(3 in)³= 3 in * 3 in * 3in = 27 in³

The volume is 27 cubic inches.

`m= 13 \ g\\v= 27 \ in^3`

Substitute the values into the formula.

`d=(13 \ g)/(27 \ in^3)`

Divide.

`d=0.481481481 \ g/in^3`

The density is 0.481481481 grams per cubic inch.