Question

Function f is defined by f(x)=3/2x+c. If f(6)=1, what is the value of f(c)?

Please don't just give me an answer, explain it so I understand. Thanks.

Answer 1

C = - 8

Explanation:

`f(x) = (3)/(2) x + c \\ \\ plug \: x = 6 \\ \\ f(6) = (3)/(2) * 6 + c \\ \\ f(6) = 3 * 3 + c \\ \\ f(6) = 9+ c \\ \\ \therefore \: 1 = 9 + c \: \{ \because \: f(6) = 1 \} \\ \\ 1 - 9 = c \\ \\ \huge \red{ \boxed{ c = - 8}}\\\\</p><p>f(c) =(3)/(2) c +(-8)\\\\</p><p>\huge \orange { \boxed{ f(c) =(3)/(2) c -8}} \\\\`