Question

Please help

solve the formula for r. suppose a merry-go-round is spinning once every 3 seconds. is the point on the outside edge has a speed of 12.56 ft per second, what is the radius of the merry-go-round? (use 3.14 for π)​

Answer 1

6 feet

Explanation:

The circumference is given by ...

C = 2πr

Since we travel that distance in 3 seconds, our speed is ...

2πr/3 = 12.56 . . . . . . feet per second

6.28/3r = 12.56 . . . . using 3.14 for π

r = 12.56(3/6.28) = 6

The radius of the merry-go-round is 6 feet.