Question

A hydrated sample weighing 20.0 g is heated in a crucible at 250°C. After cooling the sample now has a weight of 16.5 g.

What is the weight of the water lost from the sample? ______________



If the % water in the sample = g waterg of original sample x 100, what is the % water in the sample?

Answer 1

Given parameters:

Weight of hydrated sample = 20g

Temperature = 250°C

Weight after cooling = 16.5g

Unknown:

Weight of water lost from the sample = ?

Solution:

The weight of water lost from the sample;

Weight of water lost = Weight of hydrated sample - Weight of dry sample

Weight of water lost = 20g - 16.5g = 3.5g

% of water in the sample =
`(mass of water)/(mass of original sample) x 100`

Input parameters solve;

=
`(3.5)/(20) x 100`

=17.5%