Question

What is the acceleration of a mongoose that, if from rest, can reach

speeds of 19 ft/s in 8.8 seconds?
O 2.25 s
O 174.24 ft/s/s
2.25 ft/s/s
2.25 m/s

Answer 1

Step-by-step explanation:

Acceleration is change in velocity over time.

a = Δv / Δt

a = (19 ft/s − 0 ft/s) / 8.8 s

a = 2.16 ft/s/s

Answer 2

Given parameters:

Initial velocity = 0m/s

Final velocity = 19ft/s

Time taken = 8.8s

Unknown:

Acceleration

Solution:

Acceleration is the change in velocity with time of a body;

Acceleration =
`(v - u)/(t)`

v is the final velocity

u is the initial velocity

t is the time taken

input the parameters and solve;

Acceleration =
`(19 - 0)/(8.8)` = 2.16ft/s

Now, the acceleration is 2.16ft/s