Question

A bullet of mass 0.045 kg is travelling horizontally at 400 m/s when it strikes a stationary wooden block of mass 16 kg. The bullet is embedded in the block. Calculate the speed of the block with the bullet embedded within.

Velocity: m/s

Answer 1

Apply conservation of momentum

`\\ \rm\Rrightarrow m1v1+m2v2=(m1+M2)v3`

`\\ \rm\Rrightarrow 0.045(400)+16(0)=(0.045+16)V3`

`\\ \rm\Rrightarrow 18=16.045v3`

`\\ \rm\Rrightarrow v3=1.12m/s`

Answer 2

Answer:9.17 m|s

Step-by-step explanation:

explanation shown