A bullet of mass 0.045 kg is travelling horizontally at 400 m/s when it strikes a stationary wooden block of mass 16 kg. The bullet is embedded in the block. Calculate the speed of the block with the bullet

asked Sep 25, 2023 82.0k views

20 votes

by Fgul

3.7k points

Please log in or register to add a comment.

5 votes

Apply conservation of momentum

$\\ \rm\Rrightarrow m1v1+m2v2=(m1+M2)v3$

$\\ \rm\Rrightarrow 0.045(400)+16(0)=(0.045+16)V3$

$\\ \rm\Rrightarrow 18=16.045v3$

$\\ \rm\Rrightarrow v3=1.12m/s$

Kine answered Sep 28, 2023

by Kine

4.4k points

2 votes

Answer:9.17 m|s

Step-by-step explanation:

explanation shown

Kevlar answered Oct 2, 2023

4.0k points

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

4.4m questions

5.7m answers