Answer:
Explanation:
d /d x [ a ^x ]
= d/ d x [ e ^ln ( a ) x ]
= e ^ln ( a ) x ⋅ d /d x [ ln ( a ) x ]
= e ^ln ( a ) x ⋅ ln ( a ) ⋅ d /d x [ x]
= e ^ln (a ) x ln ( a ) ⋅ 1
= ln ( a ) e ^ln ( a ) x
Rewrite/simplify:
= a ^x ln ( a )
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