Question

A father's age is three times the sum

of the ages of his two children.After 5
years his age will be two times the sum
of their ages.Find the present age of the
father​

Answer 1

Let the age of father be x years and sum of the ages of his children by y years.
After 5 years,
Father's age = (x + 5) years
Sum of ages of his children = (y + 10) years
From the given information, we have:
x = 3y ...(1)
and x + 5 = 2(y + 10)
x - 2y = 15 ...(2)
From (1) and (2), we have,
3y - 2y = 15 y = 15
x = 3y = 45
Father's age = 45 years