Question

Been an hour pls help 3

Answer 1

`( {v})^(2) - ({v(0)} \: )^(2) = 2 * a * ∆x`

`( { - 10.9})^(2) - ({ - 27.7})^(2) = 2 * a * - 105 \\`

`118.81 - 767.29 = - 210 * a`

`- 648.48 = - 210 * a`

Negatives simplified :

`648.48 = 210 * a`

Divided both sides by 210 :

`a = (648.48)/(210) \\`

`a = 3.088 \: \: \frac{m}{ {s}^(2) } \\`

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I think it's the correct answer.

Hope helped.

And we're done.

Thanks for watching buddy good luck.

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Answer 2

a = 3.09 m/s^2

Explanation:

v^2 = Vo^2 +2ax

v= final velocity

Vo = initial velocity

a = acceleration

x = distance

(-10.9)^2 = (-27.7)^2 + 2(a)(-105)

118.81 = 767.29 - 210a

-210a = -648.48

a = 3.09 m/s^2