Question

How many gallons of 25% alcohol solution and 40% alcohol solution must be mixed to get 6 gallons of 30%

alcohol solution?

Answer 1

amt of 25% solution to mix=6 gal

amt of 40% solution to mix=3 gal

Explanation:

let x=amt of 25% solution to mix

9-x=amt of 40% solution to mix

25%x+40%(9-x)=30%*9

.25x+3.6-.40x=2.7

.15x=0.90

x=6

9-x=3