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What is the slope of the line that contains these point?
(13,11),(14,6),(15,1),(16,-4)

User CSP
by
8.2k points

2 Answers

4 votes

Answer:

Slope (m) = -5

Explanation:

*If all the given four points are on a straight line then; the slope derived from first two points should be equal to the slope derived from the next to points.

Let's verify this ...

For the first two points:

Slope (m) = change in y ÷ change in x =
(6 - 11)/(14 - 13) = (-5)/(1) = -5

For the next two points:

m =
(-4 - 1)/(16 - 15) = -5

*Proved ∴ points (13,11) , (14,6) , (15, 1) and (16,-4) are on the same line.

  • We can find the equation of this line and ascertain that the four points are on a single line.

Taking another point (x,y) on the line and point (13,11);

m =
(y - 11)/(x - 13) = -5

y = -5x + 65 + 11

y = -5x + 76

  • Let's graph this equation. (graph attached)
What is the slope of the line that contains these point? (13,11),(14,6),(15,1),(16,-4)-example-1
User Eezis
by
8.3k points
2 votes

Answer:

Explanation:

You can easily find the slope by using two points. Let’s use (13, 11) and (14, 6)

We look at the slope equation as: y2 - y1 divided by x2 and x1.

13 = x1 11= y1 and 14= x2 6=y2

Plug in: 6-11/14-13 and solve

Answer: -5

Hope I made sense :)

User Mathieu Lomax
by
8.5k points

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