Question

What is the equation of the line that passes through the point (6,6) and has a slope of 5/3

Answer 1

The answer is

`\huge y = (5)/(3) x - 4`

Explanation:

To find an equation of a line given the slope and a point we use the formula

`y - y_1 = m(x - x_1)\\`

where

m is the slope

( x1 , y1) is the point

From the question the point is (6,6) and slope 5/3

We have

`y - 6 = (5)/(3) (x - 6) \\ y - 6 = (5)/(3) x - 10 \\ y = (5)/(3) x - 10 + 6 \\`

We have the final answer as

`y = (5)/(3) x - 4 \\`

Hope this helps you