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Write the equation of a line that is perpendicular to y = 7/5x + 6 and that passes through the point (2,-6).

User Waylander
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1 Answer

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Answer:

y = -5/7x - 32/7

Explanation:

Perpendicular slopes are "opposite reciprocals."

7/5 goes to 5/7, then -5/7 (if you don't get it you can comment)

So the perpendicular equation line: y = -5/7x + b (you don't know the y-intercept yet)

Substitute (2, -6) because that perpendicular line is going through it.

-6 = -5/7(2) + b

-6 = -10/7 + b

-42/7 = -10/7 + b

-32/7 = b

Perpendicular line equation: -5/7x -32/7

User So
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