Question

10 points

5). A car accelerates from rest to the speed of 9.6m/s over a distance of
40.5m. Determine the acceleration of the car.

Answer 1

Step-by-step explanation:

u=0 m/s

v=9.6 m/s

s= 40.5 m

a=?

V^2=u^2 +2as

9.6^2=0+2×a×40.5

92.16=81a

a=92.16/81

a=1.14m/s^2