Question

How would logx (49) = x look like in exponential form

Answer 1

I'm assuming the given log equation is
`\log_{\text{x}}(49) = \text{x}`

If so, then the exponential form is
`\text{x}^{\text{x}} = 49`

This is because the general form
`\log_{\text{b}}(\text{x}) = \text{y}` transforms into
`\text{y} = \text{b}^{\text{x}}`

For both equations, the 'b' is the base.