Part A
I'm assuming you want the area of a circle with radius 17 yards.
We'll use the formula below
A = pi*r^2
A = (22/7)*17^2
A = (22*17^2)/7
A = 6358/7
A = 908 2/7
The sprinkler covers an area of about 908 2/7 square yards.
You'll type 908 in the left-most box
Then for the other two boxes, you'll have 2 up top and 7 down below to represent the fraction 2/7
The number 908 2/7 is a mixed number.
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Part B
You mentioned that the radius reduces to 11 yards here. We'll use the same formula as above and pi = 22/7 approximately
A = pi*r^2
A = (22/7)*11^2
A = (22*11^2)/7
A = 2662/7
A = 380 2/7
The sprinklers can water an area of about 380 2/7 square yards.
This value is also a mixed number
380 is the value in the left most box (it's the whole part)
The other two boxes are filled out the same exact way as the previous part above.