Answer:
A)196J
B)-208J
C)3467J
Explanation:
We are given that a 20 kg cylindrical mass is dropped onto the mat from a height of 1 m above the mat. During the impact, the cylinder’s vertical velocity reaches zero at the instant the mat has compressed to only 4 cm thick.
So, The Mat gets compressed by : 10cm - 4 cm = 6 cm=0.06 m
a)
Using Conservations of energy
Potential energy at the top = Kinetic energy at the point before touching the surface
Kinetic energy = mgh=
![20 * 9.8 * 1 = 196 J](https://img.qammunity.org/2021/formulas/mathematics/college/sxk1rvi9wmvkqltwzs62oc6vexcuv4cn57.png)
b)
Work done by the mat do to stop the fall of the cylinder =
![-mg(h+0.06)=-20 * 9.8(1+0.06)=-208 J](https://img.qammunity.org/2021/formulas/mathematics/college/1ayb3oyu0w21c3tma13fy9n529c0hucdiz.png)
C)
Work done=
![\text{Average force} * \text{ Compression of mat}](https://img.qammunity.org/2021/formulas/mathematics/college/mgfm8eq0amv9hsx9xu7dkm57c0cs4vp6o2.png)
![208=F * 0.06](https://img.qammunity.org/2021/formulas/mathematics/college/7fnlwyv4kksix9o2y42az0m9asq720jqhu.png)
F=3467J