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From 1995 - 2008 in the US 648 people were struck by lightening. 531 of them were men. You want to see if this observation differs from the null hypothesis, that 50% of people who are hit by lightening would be men, based on the proportion of men in the population as a whole. Calculate the probability under the normal distribution of getting a result of 531 or more (including the continuity correction). Use the binomial test with a normal approximation. What is your conclusion?

User Shawntavia
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Answer:

Because z is higher than any given value in the chart we come to the conclusion To reject null hypothesis

Explanation:

Sample proportion = p= 531/648 = 0.8194

This is the proportion of men that were hit by lightening

Null hypothesis: H0: p = 0.5

Alternate hypothesis: H1: p ≠ 0.5

Test statistics z = 0.8194-0.5/(√0.5x0.5/648)

= 0.8194-0.5/√0.0003858

= 0.3194/0.019642

= 16.26

Since the z > 1.96 (at 5% significance) we reject the null hypothesis.

Therefore in conclusion we say z is higher than given values in the chart so we reject null hypothesis.

Please check attachment!

From 1995 - 2008 in the US 648 people were struck by lightening. 531 of them were-example-1
From 1995 - 2008 in the US 648 people were struck by lightening. 531 of them were-example-2
User Grover
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