Question

Write an equation for a line that is parallel to 9x + 3y = 8 and passes through the point (-1, -4).

Answer 1

y=-3x-7

Explanation:

First you need to change the equation to slope intercept form. so the equation becomes y=-3x+8/3. now you change it point slope, y-y1=m(x-x1), y--4=-3(x--1), which also becomes y+4=-3(x+1), now you multiply. -3 times x and 1 which makes the equation, y+4= -3x+-3, then subtract from each side since its a positive number. so now the equation y= -3x-7

Answer 2

y = -3x - 7

Explanation:

turn into slope-intercept form:

9x + 3y = 8: subtract 9x to isolate y

3y = -9x + 8: divide by three to isolate again

y = -3x + 8/3 (line): Substitute y and x and replace 8/3 with b

-4 = -3(-1) + b: distribute

-4 = 3 +b: isolate b by subtracting 3

-7 = b

Substitute for b in original equation

y = -3x - 7