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A cyclist, while overtaking another bike, increases his speed uniformly from 4.2 mis to 6.3 m/s over a time interval of 5.3 s. How far does the cyclist

travel while overtaling?

User Chtenb
by
6.4k points

1 Answer

6 votes

Answer:

27.82m

Step-by-step explanation:

The distance of the cyclist can be calculated using the formula:

S = ut + 1/2 (at^2)

Where; S = distance

u = initial velocity

a = acceleration

t = time

However, to find acceleration, we use:

a = v - u/t, where v is the final velocity

According to this question, u = 4.2m/s, v = 6.3m/s, t = 5.3s

a = 6.3 - 4.2 / 5.3

a = 2.1/5.3

a = 0.396m/s^2

Hence, using S = ut + 1/2 (at^2)

S = (4.2 × 5.3) + 1/2 (0.396 × 5.3 × 5.3)

S = 22.26 + 5.56

S = 27.82

Therefore, the cyclist travel in 27.82m

User Ulrich Scholz
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7.0k points