Question

The price of Stock A at 9 A.M. Was ​$15.59 Since​ then, the price has been increasing at the rate of ​$0.12 each hour. At noon the price of Stock B was ​$16.34 It begins to decrease at the rate of ​$0.11 each hour. If the two rates​ continue, in how many hours will the prices of the two stocks be the​ same?

Answer 1

Prices of the two stocks A and B become​ same in 42 hours

Explanation:

Let t denotes number of hours in which the prices of the two stocks A and B become​ same.

Price of stock A = $15.59

Increase in price per hour = $0.12 t

Price of stock B = $16.34

Decrease in price per hour = $0.11 (t - 3)

(since price of stock A starts increasing per hour after 9 A.M. and price of stock B starts decreasing per hour after 12 noon that is 3 hours after 9 A.M.)

To find number of hours in which the prices of the two stocks A and B become​ same, solve
`15.59+0.12t=16.34+0.11(t-3)`

`15.59+0.12t=16.34+0.11(t-3)\\15.59+0.12t=16.34+0.11t-0.33\\0.12t-0.11t=16.34-0.33-15.59\\0.01t=0.42\\t=42`

So, prices of the two stocks A and B become​ same in 42 hours