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How many grams are 4.78x10*21 atoms of aluminum?
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How many grams are 4.78x10*21 atoms of aluminum?

User Alasdair McLeay
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0.214 grams. you divide the number of atoms by avogrados number (6.022*10^23) and multiply the number of moles you get by the molar mass of aluminum. you should get .214 grams!
User Frankey
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