Question

Joyce poured 200 milliliters (mL) of water into a beaker, placed a thermometer in it, and heated it until it started to boil. She recorded a temperature of 100 degrees Celsius (°C) when it started to boil. She repeated the process with 400 mL of water. What would be the temperature when this second sample started to boil?

Answer 1

473 °C

Step-by-step explanation:

The following data were obtained from the question:

Initial volume (V1) = 200 mL

Initial temperature (T1) = 100 °C

Final volume (V2) = 400 mL

Final temperature (T2) =..?

Next, we shall convert celsius temperature to Kelvin temperature. This can be obtained as follow:

T(K) = T (°C) + 273

Initial temperature (T1) = 100 °C

Initial temperature (T1) = 100 °C + 273 = 373 K

Next, we shall determine the final temperature of the water as follow:

Initial volume (V1) = 200 mL

Initial temperature (T1) = 373 K

Final volume (V2) = 400 mL

Final temperature (T2) =..?

V1/T1 = V2/T2

200/373 = 400/T2

Cross multiply

200 × T2 = 373 × 400

200 × T2 = 149200

Divide both side by 200

T2 = 149200/200

T2 = 746 K

Finally, we shall convert 746 K to celsius temperature. This is illustrated below:

T(°C) = T(K) – 273

T(K) = 746 K

T(°C) = 746 – 273

T(°C) = 473 °C

Therefore, the temperature of the second sample when it starts to boil is 473 °C