Question

3(y + 2) + y = 4(y – 1) +9
Is there a solution

Answer 1

There are no solutions Hope this helped<3 :)

Explanation:

Let's solve your equation step-by-step.

3(y+2)+y=4(y−1)+9

Step 1: Simplify both sides of the equation.

3(y+2)+y=4(y−1)+9

(3)(y)+(3)(2)+y=(4)(y)+(4)(−1)+9(Distribute)

3y+6+y=4y+−4+9

(3y+y)+(6)=(4y)+(−4+9)(Combine Like Terms)

4y+6=4y+5

4y+6=4y+5

Step 2: Subtract 4y from both sides.

4y+6−4y=4y+5−4y

6=5

Step 3: Subtract 6 from both sides.

6−6=5−6

0=−1

Answer 2

There is no solution

Explanation:

First step:

3(y + 2) + y = 4(y – 1) +9

Second step, distributing:

3y + 6 +y = 4y -4 + 9

Third step, combining like terms:

4y + 6 = 4y + 5

Fourth step:

determine if it has a solution which it does not. How do i know?

When you continue the problem 4y + 6 = 4y + 5 you need to subtract 6 on both sides which gets you -1. then you subtract 4y on both and you get

0=1. Therefore this is definitely no solution