Question

A ball of mass 0.1kg is thrown vertically upwards with an initial velocityof 80 m/s. calculate the pontential energy (i) half way up (ii) at its maximum height. what is its kinetic energy as it leaves the ground​

Answer 1

Stated below:

Step-by-step explanation:

Let's calculate the maximum height

.

H=v^2/2g=320mH=v

2

/2g=320m

PE=mgh=0.1*10*320=320 J

at halfway up PE will be half of max = 320/2=160 J

KE will be equal to PEmax=320 J.

Hope I helped! ☺