Question

What is the ratio AC: CB?​

Answer 1

D. 1 : 2

Explanation:

Given:

A(-6, -2),

B(6, 7),

C(-2, 1)

Required:

Ratio of AC : CB

SOLUTION:

Find AC:

`AC = √((x_2 - x_1)^2 + (y_2 - y_1)^2)`

Let,

`A(-6, -2) = (x_1, y_1)`

`C(-2, 1) = (x_2, y_2)`

`AC = √((-2 -(-6))^2 + (1 -(-2))^2)`

`AC = √((4)^2 + (3)^2)`

`AC = √(16 + 9) = √(25)`

`AC = 5`

Find CB:

`CB = √((x_2 - x_1)^2 + (y_2 - y_1)^2)`

Let,

`C(-2, 1) = (x_1, y_1)`

`B(6, 7) = (x_2, y_2)`

`CB = √((6 -(-2))^2 + (7 - 1)^2)`

`CB = √((8)^2 + (6)^2)`

`CB = √(64 + 36) = √(100)`

`CB = 10`

Find AC : CB

AC : CB = 5 : 10 = 1 : 2